Part two, the hardest word problem you have ever seen in your life.

After you can do the previous problem, and find the algorithm to sort the nine coins, try this one.
This one is really gross. I only ever knew one person to get this one, not counting myself.
I would go so far as to say that this problem is harder than for a married man to balance a checkbook.
Anyway, have fun with it. Here it is:

The man in the previous problem has eleven real coins instead of eight. Add in the counterfeit for a total of twelve.
In a total of three measurements, find

1)which coin in counterfeit
2)whether the counterfeit coin is heavier or lighter than the real ones.

when you dont know either to start with.



That's it. Sound easy?
The first person who emails the ENTIRE correct algorithm will get a dollar by paypal so they can go buy themself a mars bar.